View Full Version : Warning Unable to Disable
Just an Asterisk
Aug6-04, 01:22 PM
I have a program which everytime I have it compile on VC6++, there are a bunch of warnings but without any errors emitted. I have tried to disable all those warnings but none come to get effected at all by, for instance, "#pragma warning(disable: 1234)".
Is this a bug in MS C++ compiler version ? How can I make things work fine again ?
Thanks so very much for all of your help, --lol--
It'd be better just to fix your code.
- Warren
Just an Asterisk
Aug6-04, 01:46 PM
It'd be better just to fix your code.
- Warren
No, i don't think there is anything wrong in my code, my program works fine, there is also output after I execute it...
Thanks for your answer anyway
Anyone else who can help me ?
Well, it obviously functions, but it's obviously not well-written code. Show us the offending line of code, and the warning it produces, and we'll help you solve it.
- Warren
Just an Asterisk
Aug6-04, 01:49 PM
lol
:)
- aychamo
If you could draw a monkey face as your avatar, people and I would pay much attention to the nonsense you are doing and writing about..
By the way, I would like chroot get rid of this thread of mine and his out of my thread if possible because nothing about what I am doing but a meaningless smile and an I-don't-like-signature from the language I don't know...Sorry aychamo...
Just an Asterisk
Aug6-04, 01:52 PM
Okay, thanks chroot for your help..
Here is the warning I have from my compiler
'std::vector<std::basic_string<char,std::char_traits<char>,std::allocator<char> >,std::allocator<std::basic_string<char,std::char_traits<char>,std::allocator<char> > >
>::vector<std::basic_string<char,std::char_traits<char>,std::allocator<char> >,std::allocator<std::basic_string<char,std::char_traits<char>,std::allocator<char> > > >' : identifier was truncated to '255' characters in the debug information
Just an Asterisk,
I'm making an honest attempt to help you. Warnings are produced for a reason. Using a directive to disable the warning is not a good solution. You should just fix the code so it no longer produces the warning. Show it to me, and I will help you fix it.
- Warren
Just an Asterisk,
Just compile your program in release mode instead of debug mode -- unless you need to use the source-level debugger.
- Warren
http://support.microsoft.com/default.aspx?scid=kb;EN-US;q167355
- Warren
No, i don't think there is anything wrong in my code, my program works fine, there is also output after I execute it...
So, planning on working at Microsoft are we?
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