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Hello,
Why when dealing with complex numbers, as with multiplication, we use the complex conjugate operator?
Regards
So we can do complex 'division' and fractions.
Compare what happens in the following
\frac{{a + ib}}{{c + id}}*\frac{{c - id}}{{c - id}}
with
\frac{{a + ib}}{{c + id}}*\frac{{c + id}}{{c + id}}
So we can do complex 'division' and fractions.
Compare what happens in the following
\frac{{a + ib}}{{c + id}}*\frac{{c - id}}{{c - id}}
with
\frac{{a + ib}}{{c + id}}*\frac{{c + id}}{{c + id}}
I didn't get it. I mean, in telecommunication systems, when we deal with baseband signals, we deal with complex numbers, and all the time we use the complex conjugate operator, but I don't understand why and what it is mean physically.
I did expect you to work my examples out.
Which one contained the conjugate and which one leads to a single complex number result?
If you apply a formula in real analysis say 27*3 you want the simple answer 81, not something more difficult than you started with such as
{\left( {\sqrt 9 } \right)^2}*{\left( {\sqrt 9 } \right)^2}
The same is true of complex numbers.
What does simple multiplication by a conjugate yield by the way ( a real number)?
HallsofIvy
Mar7-10, 09:42 AM
The product of a complex number and its conjugate has the nice property that is a real number- and for any z other than 0 z*\overline{z} is a positive real number.
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