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JasonRox
Aug8-04, 03:02 PM
This is from Special Relativity, but it is not relevant to my question anyways.

I am trying to simplify this:

{\Delta}t = \frac{\ell}{c} \left[ \frac{1}{1- \beta^2} - \frac{1}{\sqrt{1 - \beta^2}} \right]

- TO -

{\Delta}t \approx \frac{\ell}{2c} \beta^2

For small x, (1 + x)^n \approx 1 + n x

NOTE: Problem SOLVED. Feel free to try this out yourself. Make x = -\beta^2, it makes it easier, or I think it does.

uart
Aug9-04, 01:50 AM
Yep, It's called using the first two terms of the binomial expansion and it comes in very handy. :)

TenaliRaman
Aug9-04, 08:07 AM
One has to be careful , though approximations are common inphysics ... though it really demands sometimes to think how much approximate approximations should be :P

http://mathworld.wolfram.com/BernoulliInequality.html