IooqXpooI
Aug10-04, 11:35 AM
I don't know if this is true or not, and I have a feeling that it has already been proven otherwise, but I think that the forces applying to antimatter are flipped.
For instance, a positron and an electron would repel, and a positron and a proton would attract(don't mind the inserting of the electron, it was the only negatively charged particle that I could think of that was of the matter family).
If this is so, then two like pairs of different matter families would attract, and also, be quite interesting(so interesting, that this is provably proved wrong due to the fact that I would have heard of it no matter how much I miss the Physics news).
Imagine this- you have a positron on one side of a box, with that side charged positively with matter, so it is attracted, and a proton in the same state on the other(wall charged negatively, etc.). Now imagine that you insert an electron. If you do so, it will be repelled from the Antimatter and attracted with \frac{kQq}{r^2} + \frac{r^2}{kQq} to the proton, due to the repulsion and the skewed logic used by me to find the inverted formula is the Antimatter version(thus stating that they use Reverse Gravity as we use Gravity, etc.).
Soo, evaluate this and try not to give too much criticism, for I know that it is hard to hold back with something like this...;)
For instance, a positron and an electron would repel, and a positron and a proton would attract(don't mind the inserting of the electron, it was the only negatively charged particle that I could think of that was of the matter family).
If this is so, then two like pairs of different matter families would attract, and also, be quite interesting(so interesting, that this is provably proved wrong due to the fact that I would have heard of it no matter how much I miss the Physics news).
Imagine this- you have a positron on one side of a box, with that side charged positively with matter, so it is attracted, and a proton in the same state on the other(wall charged negatively, etc.). Now imagine that you insert an electron. If you do so, it will be repelled from the Antimatter and attracted with \frac{kQq}{r^2} + \frac{r^2}{kQq} to the proton, due to the repulsion and the skewed logic used by me to find the inverted formula is the Antimatter version(thus stating that they use Reverse Gravity as we use Gravity, etc.).
Soo, evaluate this and try not to give too much criticism, for I know that it is hard to hold back with something like this...;)