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A 2.50kg object is moving along the x-axis at 160m/s. as it passes the origin, two forces F1 and F2 are applied, both in the y direction f1=15N in the j direction. The forces are applied for 3.00s after which the object is at the point x=4.80m y=10.8m. Find f2.
can anyone figure out how to do this?
tiny-tim
Apr12-10, 03:25 AM
Hi sheers! Welcome to PF! :smile:
A 2.50kg object is moving along the x-axis at 160m/s. as it passes the origin, two forces F1 and F2 are applied, both in the y direction f1=15N in the j direction. The forces are applied for 3.00s after which the object is at the point x=4.80m y=10.8m. Find f2.
can anyone figure out how to do this?
yes, you can :wink: …
use good ol' Newton's second law (F = ma), and the standard constant acceleration equations …
what do you get? :smile:
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