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philtered
Apr18-10, 06:40 PM
1. The problem statement, all variables and given/known data
How many grams of ice at 0°C could be melted by the heat produced when 10.0g of ethanol is burned?


2. Relevant equations
So I wrote out the combustion reaction:
C2H5OH +3O2 ---> 2CO2 + 3H2O


3. The attempt at a solution
First I though I had to find heat of formation for that reaction, which I found to be -1235.6kJ (So this would be the heat given off when ethanol is burned correct?)
Hf=products-reactants
Hf=[-393.6(2)+-242(3)]-[-277.6+0]
Hf=-1235.6kJ

I wasn't sure if I had to use that number or if I had to just pull the Hf number off my chart for ethanol (-277.6kJ)

I have the answer given to me, but I'm stuck at converting my kJ to g of water. (Answer is 802g)

Tried: 1235.6kJ[1mol/6.03kJ][18.02g/1mol]

Dickfore
Apr18-10, 07:08 PM
You need to constants. The latent heat of fusion of ice (let us denote it by L_{f}) and the energy released by burning a unit mass of ethanol (let us denote it by q). Then, you simply have:

Heat needed to melt mass m(\texrm{ice}) = L_{f} \cdot m(\textrm{ice})

Heat released by burning mass m(\textrm{ethanol}) = q \cdot m(\textrm{ethanol})

These are equal, so, you have an equation for m(\textrm{ice}):



m(\textrm{ice}) = \frac{q}{L_{f}} m(\textrm{ethanol})

philtered
Apr18-10, 11:52 PM
Thanks for the help. It worked out with that. Also the q value I was using was wrong, had forgot to take into account the 10g of ethanol being burned.

Dickfore
Apr18-10, 11:53 PM
cool. am i right to assume you're a chem student?

philtered
Apr19-10, 12:04 PM
Yeah I am. Right now just the high school course, next year I'm doing Physics with a minor in Chem