Solving for Length of Solenoid Wire Using Ampere's Circuital Law

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SUMMARY

The discussion focuses on calculating the length of wire used in a solenoid based on Ampere's Circuital Law. Given a solenoid with a length of 1.33 cm, a diameter of 2.6 cm, and a current of 17.8 A, the magnetic field inside is 22.4 T. The key equation utilized is B = μ₀ N i / L, where μ₀ is the permeability of free space. The solution involves determining the number of turns (N) using the known values of magnetic field (B) and solenoid length (L).

PREREQUISITES
  • Understanding of Ampere's Circuital Law
  • Familiarity with magnetic field calculations in solenoids
  • Knowledge of the permeability of free space (μ₀)
  • Basic algebra for solving equations
NEXT STEPS
  • Study the derivation of the magnetic field formula for solenoids
  • Learn about the significance of the permeability of free space (μ₀)
  • Explore practical applications of solenoids in electrical engineering
  • Investigate the relationship between current, turns, and magnetic field strength
USEFUL FOR

Physics students, electrical engineers, and anyone interested in electromagnetism and solenoid design will benefit from this discussion.

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Homework Statement


A solenoid of 1.33cm long and 2.6cm in diameter carries a current of 17.8A . the magnetic field inside the solenoid is 22.4 T . find the length of the wire forming the solenoid.


Homework Equations


B= Uo N i / L .


The Attempt at a Solution



the problem is i don't find the value of N? as it cannot be 1 for solenoid. so how do i solve this problem.
 
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You can find the ratio N/L from the field and the current and since you know that L = 1.33 cm, you can find N. Does this help?
 

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