Power Rating of 570 W Heaters in Series: 1140 W

  • Thread starter Thread starter GreenDinos
  • Start date Start date
  • Tags Tags
    Power Voltage
Click For Summary

SUMMARY

The power consumed by two 570 W heaters connected in series to a 120V AC voltage is 1140 W. Each heater maintains its individual power rating of 570 W, resulting in a combined power consumption of 1140 W when connected in series. This is due to the fact that while the voltage remains constant, the current is divided between the heaters. The relationship between power, voltage, and current is governed by the formula P = V × I.

PREREQUISITES

  • Understanding of Ohm's Law
  • Basic knowledge of electrical power calculations
  • Familiarity with series circuit configurations
  • Knowledge of AC voltage systems

NEXT STEPS

  • Study the implications of connecting electrical devices in series versus parallel
  • Learn about power distribution in AC circuits
  • Explore the concept of resistance in series circuits
  • Investigate the effects of voltage drop across series-connected devices

USEFUL FOR

Electrical engineers, technicians, and students studying circuit theory or working with AC power systems will benefit from this discussion.

GreenDinos
Messages
10
Reaction score
0
Q20-9. The power rating of a 570 W heater specifies the power consumed when the heater is connected to an ac voltage of 120V. What is the power consumed by two of these heaters connected in series, connected to the same voltage?

570 W
285 W
1140 W
2280 W
142.5 W

ok, my original thinking was that the 120V will supply 570 W of power and that two in a series would still have a total power of 570W (285W each)...but that was wrong...so is it double the power (1140W)- is the power consumed still 570W for each heater- and so 1140 is the total?

thanks
 
Physics news on Phys.org
Power is voltage times current. Ohm's law says voltage is current times resistance.

[tex]P = V \cdot I = \frac{V^2}{R}[/tex]

Solving for resistance:

[tex]R = \frac{V^2}{P}[/tex]

Replacing R with 2R:

[tex]P_{\textrm{both}} = \frac{V^2 \cdot P}{2 V^2} = \frac{P}{2}[/tex]

- Warren
 
for your response!

In this scenario, when two 570 W heaters are connected in series, the total power consumed would be 1140 W. This is because when heaters are connected in series, the voltage remains the same, but the current is divided between the two heaters. So each heater would still consume 570 W, but together they would consume a total of 1140 W. This is because power is calculated by multiplying voltage by current, and in this case, the voltage remains constant at 120V for both heaters. Therefore, the power consumed by two 570 W heaters connected in series would be 1140 W.
 

Similar threads

  • · Replies 1 ·
Replies
1
Views
3K
  • · Replies 7 ·
Replies
7
Views
3K
  • · Replies 12 ·
Replies
12
Views
1K
Replies
16
Views
6K
Replies
4
Views
7K
  • · Replies 6 ·
Replies
6
Views
2K
Replies
25
Views
3K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 4 ·
Replies
4
Views
9K
  • · Replies 4 ·
Replies
4
Views
2K