Finding the Displacement of a Duck Undergoing Multiple Forces

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Homework Help Overview

The problem involves calculating the displacement of a duck subjected to multiple forces while it paddles in water. The scenario includes forces acting in different directions and an initial velocity, with the goal of determining the resultant displacement over a specified time period.

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Approaches and Questions Raised

  • Participants discuss finding the x and y components of acceleration and displacement using kinematic equations. There are attempts to break down the forces into components and calculate the resulting acceleration. Questions arise regarding the correctness of calculations and the interpretation of angles related to displacement versus force.

Discussion Status

The discussion includes various attempts to clarify the calculations and identify mistakes. Some participants provide feedback on specific steps, while others express uncertainty about the approach. There is no explicit consensus on the correct method, but guidance is being offered to refine the calculations.

Contextual Notes

Participants are working under the constraints of a homework assignment, which may limit the information they can share. There is an emphasis on checking assumptions and ensuring that all components of motion are considered in the calculations.

pinky2468
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Here is the question: A duck has a mass of 2.5kg. As the duck paddles, a force of 0.10N acts on it in a direction due east. In addition, the current of the water exerts a force of 0.20N in a direction of 52degrees south of east. When the forces begin to act, the velocity of the duck is 0.11m/s in a direction due east. Find the magnitude and direction (relative to due east) of the displacement that the duck undergoes in 3.0s while the forces are acting.
SO, I attemted to find the acceleration for the x and y and then use the tangent-1 to find the angle and the x=volt + 1/2a(t)squared. Again not getting the answer in the back of the book 0.78m, 21degrees south of east
Obviously I am approaching this problem wrong?! Any advice??
 
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Find the x and y components of the acceleration. Then use kinematic formulas to find the x and y components of the displacement. That sounds like what you are saying you did. Show your work so we can check it out.
 
Rx=.20N(cos 52) + .10(cos 0)=.2231N Ry= .20(sin 52) + .10(sin 0)=.1576N

Ax=.2231N/2.5kg= .08924 Ay=.1576N/2.5kg= .0252

tan-1(.0252/.08924)=15.8degrees(wrong answer)

x=.11m/s(3.0s) + 1/2(.08924m/s^2)(3.0s)^2= wrong answer!

What step am I missing or am I completely off track?
 
You are not off track, you are just making mistakes.
pinky2468 said:
Rx=.20N(cos 52) + .10(cos 0)=.2231N Ry= .20(sin 52) + .10(sin 0)=.1576N
OK.

Ax=.2231N/2.5kg= .08924
OK.
Ay=.1576N/2.5kg= .0252
Not OK. Do over.
 
Pinky did you see that the initial velocity has only a non-zero component which is its horizontal?
 
I spoke too soon before. You are a bit off track. In addition to your mistake that I already pointed out:
pinky2468 said:
tan-1(.0252/.08924)=15.8degrees(wrong answer)
It looks like you are finding the angle of the force. But you should be finding the angle of the displacement, not the force.
x=.11m/s(3.0s) + 1/2(.08924m/s^2)(3.0s)^2= wrong answer!
That's just the x-component! Don't forget to find the y-component, and then the total displacement.
 
OK! I finally got it! Thanks!
 

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