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Jim4592
Sep12-10, 09:42 PM
1. The problem statement, all variables and given/known data

Elemental (metallic) aluminum (Al) is reacted with HCl to yield aluminum chloride (AlCl3) and hydrogen gas (H2). How many grams of metallic aluminum would be required to produce 1 gram of pure hydrogen gas?


2. Relevant equations

Al + HCl --> AlCl3 + H2

Balance Reaction: 2 Al + 6 HCl --> 2 AlCl3 + 3 H2



3. The attempt at a solution

let Z = the amount of Al needed

Z g Al * (1 mol Al / 26.98 g Al) * (3 mol H2/2 mol Al) * (2.02 g H2/1 mol H2) = 1 g H2

(6.04764 * Z) / 53.96 = 1

Z = 8.922 g Al

I was hoping someone could look over this and see if did the correct process and came up with the right answer.

Thanks!

salva
Sep12-10, 10:29 PM
You're correct