Easy physics problem, finding forumula

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SUMMARY

The discussion focuses on calculating the force between two parallel wires using the formula F_12 = μ₀*L*I₁*I₂/(2πD). The user initially misinterprets the variables, particularly the lengths and currents involved. The correct approach involves recognizing that the forces on the wires are equal and opposite, and substituting the known values accurately into the equation. The external magnetic field must also be considered in the calculations for accurate results.

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rdn98
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I have included a picture.

Question:
What is the force on each wire if B = 1.656T, i = 10A, L1 = 7cm and L2 = 14cm?

Now, I have checked my physics book, and the equation I have found is
F_12 = mu_0*L*I1*I2/(2*pi*D)

where D is the distance between the two wires, and L is the length of one wire.

However, I tried that formula in the computer, and it doesn't work. I let L =L2 (m), D=L1 (m), I have tried I1=10 and I2=+/- 10...but it didn't work.

I'm thinking there is another round about way to do this, but I don't know what. CAn someone lend me a hand?
 

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Hey

Ok, the formula is right, you got all the information right under your nose. You're just interpreting wrong.

We know that the wires, let's denote them A and B, are going to have equal and opposite forces.

The equation is F_BA = I_B*L X(cross) B

F_BA = I_B*L * mu_0*I_A/(2*pi*D)
Ok, well, your B is already given to you, which you can substitute for the mu_0*I_A/(2*pi*D).

Let I_B = current, and your L = L2 and that should do the trick.

Well
 
Did you include the external magnetic field?
 

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