How do I calculate the total energy from an electron-positron collision at .9c?

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SUMMARY

The total energy produced by an electron-positron collision, each moving at 0.9c, can be calculated by determining the relativistic kinetic energy of one particle and then doubling it, followed by adding their rest energies. In this scenario, the center of mass (CM) frame and the laboratory frame are equivalent, simplifying the calculations. Lorentz transformations are not necessary for this specific case, as the velocities are aligned in a head-on collision.

PREREQUISITES
  • Understanding of relativistic kinetic energy calculations
  • Familiarity with the concept of rest energy (E=mc²)
  • Knowledge of the Lorentz transformation principles
  • Basic principles of particle physics and collisions
NEXT STEPS
  • Study the derivation of relativistic kinetic energy formulas
  • Learn about the implications of the center of mass frame in particle collisions
  • Explore advanced topics in particle physics, such as annihilation processes
  • Investigate the effects of varying velocities in particle collisions using Lorentz transformations
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Physics students, educators, and researchers interested in particle collisions and relativistic energy calculations.

cragar
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Homework Statement


Find the total energy produced by an electron positron collision each moving at
.9c , it is a head on collision.

The Attempt at a Solution




Can i just find the relativistic Kinetic energy of one moving at .9c
and then double it and add it to their rest energies and this would be the total energy .
Or do i need to do Lorentz transformations to see what velocity the one particle perceives the other .
 
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cragar said:

The Attempt at a Solution




Can i just find the relativistic Kinetic energy of one moving at .9c
and then double it and add it to their rest energies and this would be the total energy.
Yes. It's usually customary to calculate in either the CM or the lab frame, and in this problem they are one and the same.
 
ok thanks for the help
 

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