how many moles of NH3 in the supplied solution0.2 M NH3 in 2 M Nh4NO3

[everscern]

1. The problem statement, all variables and given/known data

How many moles of NH3 are in 2ml of supplied solution: 0.2 M NH3 in 2 M Nh4NO3

Ans to be given in mmol

2. Relevant equations

Concentration = mol/ L

3. The attempt at a solution

Ratio of NH3 : NH4NO3 = 1: 10

2 / 11 = 0.182 ml

0.2 mol/L * 1L/ 1000ml * 0.182 ml * 1000 = 0.0364 mmol

[sjb-2812]

1. The problem statement, all variables and given/known data

How many moles of NH3 are in 2ml of supplied solution: 0.2 M NH3 in 2 M Nh4NO3

Ans to be given in mmol

2. Relevant equations

Concentration = mol/ L

3. The attempt at a solution

Ratio of NH3 : NH4NO3 = 1: 10

2 / 11 = 0.182 ml

0.2 mol/L * 1L/ 1000ml * 0.182 ml * 1000 = 0.0364 mmol

I'm not sure why you're calculating the ratio of ammonia to ammonium salt, and then not using it? What's the 2/11 calculation for?