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chem1guy
Sep25-10, 01:23 PM
1. The problem statement, all variables and given/known data


above each square ince of the earths surface is 14.7 pounds of air. the density of air at sea level is 1.27g/l. the earth is 7930 miles in diameter and has a mass of 5.98x10^24kg.

use this data to determine the mass in kg of the earths atmosphere

determine the average density in g/mm

2. Relevant equations
4pieR2


3. The attempt at a solution
14.7 lb air/in2 x 1kg/2.205lb x (39.37in/1m)2=1.03x10'4/m2 air above surface
then
A=4pieR2=1.97x10'8mi2 x (1km/.6214)=5.11x10'14m2

then multiply the answers for 1.534x1017kg

is that close for the "a" part?

thanks

D H
Sep25-10, 03:08 PM
is that close for the a part?
No.

Which are your symbols, and what is all this addition stuff?

Note: the "pounds" per square inch is a unit of force, not mass.

chem1guy
Sep26-10, 09:46 AM
sorry typed it wrong. i reposted my work. i don't know where else to go

D H
Sep26-10, 09:59 AM
I'll be a bit more explicit in where you went wrong.

3. The attempt at a solution
14.7 lb air/in2 x 1kg/2.205lb x (39.37in/1m)2=1.03x10'4/m2 air above surface
The "pounds" in "pounds per square inch" is a unit of force, not mass. Your mistake results from assuming it is a unit of mass.

chem1guy
Sep26-10, 10:12 AM
ok thanks. i'll try to look up the difference b/c we have not covered this distinction in class

chem1guy
Sep26-10, 10:32 AM
14.7psi x 702771g/m2 x 1kg/1000g= 10331kg/m2 of air above surface
A=4pieR2=1.97x10'8mi2 x (1km/.6214)=5.11x10'14m2 surface area

5.29x10'18 mass of atmosphere!?

D H
Sep26-10, 01:34 PM
Looks good, but where did you come up with 702771g/m2?

chem1guy
Sep26-10, 02:03 PM
I looked it up the conversion. I thought it might be in the problem but I can'tseem to find it working backwards

chem1guy
Sep26-10, 02:35 PM
Volume of a sphere?? Does it have to do with density