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fresh
Sep20-04, 12:14 AM
the initial diffferential question is
y' = ty(4-y)/(1+t)

i isolated the variables and integrated

what i have is
(1/4)ln4y - (1/4)ln(4-y) = t - ln(t+1) + c

now i am supposed to express the general solution explicitly but i am don't know how to solve for y. any sort of suggestion would be greatly appreciated. thanks.

Tide
Sep20-04, 12:40 AM
Combine the logs on each side noting ln a - ln b = ln (a/b) and proceed from there! :-)