Calculate Energy & Wavelength of Hydrogen Atom Absorption

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SUMMARY

The discussion focuses on calculating the energy and wavelength of hydrogen atom absorption, specifically for a wavelength of 4055 nm. The energy absorbed is calculated using the formula E = (h*c)/λ, resulting in 4.905 x 10^-20 J. The relationship between the initial and final quantum numbers (ni and nf) is established through the equation 1/nf^2 - 1/ni^2 = -0.0225, leading to the conclusion that ni = 5 and nf = 4. Participants express a desire for alternative methods to solve for these quantum numbers beyond guess and check.

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The hydrogen atom can absorb light of wavelength 4055nm. Determine the inital and final values of n associated with this absorption.

Well i figured out the Energy it absorbed

(h*c)/(wavelength)

= ((6.63*10-34)*(3*10^8))/(4055/10^9)

=4.905 * 10^-20 J

so 4905*10^-20 = -2.18*10-18*(1/nf^2 - 1/ni^2)

1/nf^2 - 1/ni^2 = -.0225

How do i solve these two unknowns, other than guess and check?
 
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I think its pretty much guess and check from there. I get 5 and 4.
 
Healey01 said:
I think its pretty much guess and check from there. I get 5 and 4.

ya i got the same answers... but i just wanted to see if anyone has a different method to solve this problem .
 

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