Solving [problem2.26]: A Conical Surface's Potential Difference

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SUMMARY

The discussion focuses on solving problem 2.26 from Griffiths' "Introduction to Electrodynamics," which involves calculating the potential difference between the vertex and the center of the top of a conical surface with a uniform surface charge density . The solution requires performing an integral in spherical coordinates (r, theta, phi), noting that the phi components cancel out due to symmetry. It is essential to integrate over both the radial distance and the angle, referencing integral techniques found in calculus resources for assistance.

PREREQUISITES
  • Understanding of electrostatics and surface charge density
  • Familiarity with Griffiths' "Introduction to Electrodynamics"
  • Knowledge of spherical coordinates in calculus
  • Ability to perform integrals involving multiple variables
NEXT STEPS
  • Review spherical coordinate integration techniques
  • Study potential calculations for different charge distributions
  • Explore advanced topics in electrostatics from Griffiths' textbook
  • Practice solving similar problems involving conical geometries
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Students of electromagnetism, physics educators, and anyone tackling advanced calculus problems related to electrostatics and charge distributions.

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I have a problem from Griffiths Introduction to EM

[problem2.26] A conical surface (an empty ice-cream cone) carries a uniform surface charge <sigma>. The height of the cone is h, and the radius of the top is R. Find the potential difference between points a(the vertex) and b (the center of the top)

The integral is so complicated. Anyone has the solution?

Thanks a lot.
 
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Do the integral in spherical coordinates (r,theta,phi). The integral doesn't depend on phi (the phi components cancel out) and since r and theta are constant for the geometry of an ice cream cone, the integral is just over phi. Use the integral that takes you from the charge distribution directly to the potential.
 
Whoops,

You do need to integrate over dR as well. Look up that integral in the back of a Calculus book. You'll have to play around with it a little
 

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