Circuit Problem: Finding the Correct Solution for a Voltage Calculation

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SUMMARY

The discussion centers on solving a circuit problem involving voltage calculations with two proposed solutions. The first solution calculates the current Ix as 2.86 mA and the output voltage Vo as 11.4 V, while the second solution finds Ix to be 0.00998 mA and Vo as 39.9 V. The participants are seeking clarification on which solution is correct and where any mistakes may lie. The problem involves applying Kirchhoff's Current Law (KCL) and series resistance calculations.

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ninaricci
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circuit problem, please need help??

Hi,
I am going to be so pleased if somebody helped me with the problem in the attached file
best wishes :confused: :confused:
here is my solution but i do not know where the mistake is
solution number 1

4-ix-vo/10=0
V of 20k = vo of 10 = 4Ix
Using eq 1…..4-ix-4Ix/10=0
4-1.4Ix=0
4=1.4Ix
4/1.4=Ix
= 2.86ma
Vo=4*2.86 = 11.4v


Solution number 2

Combing 10 kohm and 10 kohm = 20 since they are in series
Voltage of 20 kohm the resultant is = 4000Ix
4000Ix/20 = I of 20 kohm……200Ix = I of 20 kohm
Kcl
4mA-Ix –Iof vo = 0
4ma-Ix – 4000Ix/10
4ma-Ix – 400Ix = 0
4ma -401Ix =0
4ma = 401 Ix
4ma/401 = Ix
Ix= 0.00998mA
Vo = Io of vo * 10 kohm
4mA-0.00998-Io of vo = 0
Io of vo = 3. 99 ma
Vo = 3.99* 10 = 39 .9V
which solution is correct and if thre is amistake where is it
 

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ninaricci,

please post what you've tried for this problem.

I'm moving the thread to homework help.
 
Too late, I gave her an answer in the General Physics forum. She posted it there too.
 

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