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View Full Version : Boundary terms in hilbert space goes vanish


notojosh
Oct19-10, 06:27 PM
Thant helped. thank you!!

Fredrik
Oct19-10, 06:37 PM
Can you give a more exact reference? A link to the exact page at google books would be the best way to reference it.

I assume it has something to do with the common claim that square integrable functions must go to zero as the variable goes to infinity (\psi(x)\rightarrow 0 when x\rightarrow\infty), which is actually wrong. (There are counterexamples. See this thread (http://www.physicsforums.com/showthread.php?p=2645354)). However, I think \psi(x) must go to zero as x goes to infinity if Q\psi (where Q is the position operator) is square integrable. Maybe it also has to go to zero if P\psi (where P is the momentum operator) is square integrable? (I don't have time to think that through right now).