PDA

View Full Version : velocity+acceleration


UrbanXrisis
Sep21-04, 07:00 PM
A particle moves along the x axis accoring to the equation x=2.00+3.00t-t^2 where x is in meters and t is in time. At 3.00s what is the velocity and acceleration. For velocity, I would just take the derivative of x=2.00+3.00t-t^2 and sub in 3.00s and for the acceleration I would have to get the second derivative of x=2.00+3.00t-t^2 and sub in 3.00 seconds. Is this correct?

Sirus
Sep21-04, 07:08 PM
I believe so. Hurray for calculus!:)