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lavster
Oct23-10, 05:31 AM
Can someone confirm that \int J_0(ax)xdx=\frac{J_1(ax)x}{a}? I can only find the solution if J(x) but i want J(ax) so what i did above makes logical sense to me but i cant find it anywhere. thanks

JJacquelin
Oct23-10, 09:51 AM
That's alright.
Just let x=t/a and dx=dt/a in order to prove it.

lavster
Oct23-10, 01:19 PM
excellent - thanks!