Calculating Molar Mass of an Unknown Gas from Effusion Rate

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SUMMARY

The discussion focuses on calculating the molar mass of an unknown gas using its effusion rate compared to pure methane (CH4). The measured effusion rate of the unknown gas is 24.0 mL/min, while methane's rate is 47.8 mL/min. According to Graham's law of effusion, the rates of effusion are inversely proportional to the square root of their molar masses. By applying this principle, the molar mass of the unknown gas can be determined using the known molar mass of methane, which is 16 g/mol.

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  • Understanding of Graham's law of effusion
  • Basic knowledge of molar mass calculation
  • Familiarity with gas laws
  • Ability to perform ratio and proportion calculations
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  • Study the calculation of molar mass for various gases
  • Explore the relationship between molecular weight and gas behavior
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Lilly
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effusion rates...please help!

Could someone please explain to me how to do this question...
The rate of effusion of a particular gas was measured to be 24.0 mL/min. Under the same conditions the rate of effusion of pure methane gas, (CH4) is 47.8 mL/min. What is the molar mass of the unknown gas?
 
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Effusion rates are indirectly proportional with the molar mass; if the molecule is bigger, it can't move fast. So the particular gas has a greater molar mass.

Calculate methane's molar mass by taking C:12, and H:1 grams/mol, and find the unknown gas' molar mass.

Regards,
chem_tr
 
Last edited:

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