Calculate [D, r] and [D, p] with Dilatation Operator

  • Thread starter Thread starter Goodwater
  • Start date Start date
  • Tags Tags
    Operator
Click For Summary

Homework Help Overview

The discussion revolves around the dilatation operator defined as D = r * p, where participants are tasked with calculating the commutators [D, r] and [D, p]. The context involves quantum mechanics and operator algebra.

Discussion Character

  • Exploratory, Assumption checking

Approaches and Questions Raised

  • Participants question the definitions of the variables r and the operation represented by * in the context of the dilatation operator. Clarifications are sought regarding the notation and the specific form of the operator D.

Discussion Status

The discussion is ongoing, with participants clarifying the notation and definitions involved. One participant has confirmed the form of D and specified that r is not the square root of the position vector. There is an indication of a method to approach the calculation of the commutators, but no consensus or final method has been established yet.

Contextual Notes

There are uncertainties regarding the notation and definitions of the variables involved, which are crucial for the calculations. The original poster expresses a lack of familiarity with the notation conventions in the forum.

Goodwater
Messages
2
Reaction score
0

Homework Statement


Consider the dilatation operator: D = r * p

Calculate [D , r] and [D , p]

Homework Equations





The Attempt at a Solution


 
Physics news on Phys.org
It is not clear what r stand for and what * stands for. Do you mean

[tex]D=\mathbf{r}\cdot\mathbf{p}=xp_x+yp_y+zp_z[/tex]?

Do you mean [itex][D,\mathbf{r}][/itex] or [itex][D,r][/itex] where [itex]r=\sqrt{\mathbf{r}^2}[/itex]. These details are important.
 
Hi.

Thank you for reply.

You are correct: D = xpx + ypy + zpz
I meant [D,r] where r is not square root.

I hope this is more understandable, as this is my first post I don't know how to get the notations right:)
 
The you calculate using [itex][AB,C]=A[B,C]+[A,C]B[/itex], for isntance

[tex][xp_x,x]=x[p_x,x]+[x,x]p_x=\ldots[/tex]

Mostly you will get zeros, but occasionally you will get a term that will contribute.
 

Similar threads

  • · Replies 46 ·
2
Replies
46
Views
6K
  • · Replies 8 ·
Replies
8
Views
2K
  • · Replies 2 ·
Replies
2
Views
3K
  • · Replies 1 ·
Replies
1
Views
3K
Replies
1
Views
2K
  • · Replies 10 ·
Replies
10
Views
4K
  • · Replies 7 ·
Replies
7
Views
2K
Replies
5
Views
2K
Replies
1
Views
3K
  • · Replies 14 ·
Replies
14
Views
3K