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y35dp
Nov24-10, 08:45 AM
I know this should be easy and the answer will be glaringly obvious in hindsight but my brain is fried and I can't for the life of me figure this out. My problem is this I have a function as follows;

V = \sum\lambdai,j,k hihjhk (summation over i,j,k where i,j,k = 1,2,3)

I cant work out if this is

V = \lambda1,1,1h13 + \lambda1,1,2h12h2 + ... + \lambda2,3,1h2h3h1 +...

with every permutation of 1, 2 and 3, this should be simple as it is taken as a given in my problem but it is driving me insane.

HallsofIvy
Nov24-10, 09:15 AM
Yes, what you have so far is correct. And, since there are 3 indices and each can take on 3 values, there will be 3^3= 27 terms in the sum.
It would help to have a "process" for working through them- I recommend changing the last index through 1, 2, 3, then the next, etc.- just like an odometer turns over in a car.

i,j,k= 1,1,1; 1,1,2; 1,1,3; 1,2,1;1,2,2; 1,2,3; 1,3,1; 1,3,2; 1,3,3;
will be the first 9 terms.
The next 9 will be exactly the same but with first number 2 and the last 9 with first number 3.

y35dp
Nov24-10, 09:22 AM
Thank you, you may just have rescued my mental health