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Faiza
Sep28-04, 09:23 PM
A man pushes a heavy load across a horizontal floor. What is the work done by gravity on the load?
a. The work depends on the weight of the load.
b. The work done by gravity is negative.
c. The work done by gravity is zero.
d. The work done by gravity is positive.

Cyclovenom
Sep28-04, 09:29 PM
Remember Work is the scalar product of displacement and Force, so what's the angle between the displacement and the Force of Gravity (weight)?

Faiza
Sep28-04, 09:40 PM
no i dun think so

Faiza
Sep28-04, 09:43 PM
the work done by a constant force F on a particle is defined as the product of the component of the force in the direction of the particles displacement and the magnitude of the displacement. If F makes an angle theta with the displacement then the work done by f is W=Fdcos thetha
if thetha is 90 degress its zero?

Faiza
Sep28-04, 09:45 PM
i checked the answer and its zero

Faiza
Sep28-04, 09:46 PM
:{ lol i dun get it

Cyclovenom
Sep28-04, 09:46 PM
no i dun think so

what you don't think?

\frac{dW}{d \vec{x}} = \vec{F}

dW = \vec{F} \cdot d \vec{x}

Scalar Product or Point Product

\vec{A} \cdot \vec{B} = | \vec{A}||\vec{B}|cos\theta

where \theta is the angle between the two vectors.

Cyclovenom
Sep28-04, 09:50 PM
the work done by a constant force F on a particle is defined as the product of the component of the force in the direction of the particles displacement and the magnitude of the displacement. If F makes an angle theta with the displacement then the work done by f is W=Fdcos thetha
if thetha is 90 degress its zero?

What's the cosine of 90 degrees?

Faiza
Sep28-04, 09:52 PM
Cos(90)=0??????????

Cyclovenom
Sep28-04, 09:52 PM
Cos(90)=0??????????

Yes, so the work done by Gravity is??? :smile:

Faiza
Sep28-04, 09:56 PM
Zero................... Lol