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How do we know that the (effective) dimensionality of "space" is three in a typical physical theory?
tom.stoer
Nov30-10, 01:13 AM
a) because we see it
b) because we can measure it, e.g. via the Coulomb law which shows a behaviour like U(r) ~ r-(D-2)
c) because there are a huge number of physical predictions depending on the dimensionality (besides the Coulomb law there are the gravitational potential, diffusion processes, ...)
a) because we see it
b) because we can measure it, e.g. via the Coulomb law which shows a behaviour like U(r) ~ r-(D-2)
c) because there are a huge number of physical predictions depending on the dimensionality (besides the Coulomb law there are the gravitational potential, diffusion processes, ...)
Thank you for breaking it down into parts:
a') Because we can't see/perceive "further/higher".
b',c') Taking (a'), how can I make sure it will not affect (b,c)?
tom.stoer
Nov30-10, 07:16 AM
I think you can't.
a) is certainly reasonable in the macroscopic domain
b) is valid in the microscopic domain at least at scales currently measured at the LHC (there is a minor chance to find indications for large extra dimensions at the LHC which would mean that the effective dimension D becomes energy dependent D(E) and will deviate from 3 at high energies E)
c) just means that there are other processes from which such deviations could be determined, e.g. gravitational interactions
Thank you for breaking it down into parts:
a') Because we can't see/perceive "further/higher".
b',c') Taking (a'), how can I make sure it will not affect (b,c)?
yes i have the same confusion
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