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physicsss
Sep29-04, 02:37 AM
A motorboat traveling at a speed of 2.4 m/s shuts off its engines at t = 0. How far does it travel before coming to rest if it is noted that after 3.0 s its speed has dropped to half its original value? Assume that the drag force of the water is proportional to v.
physicsss
Oct1-04, 02:40 AM
....anyone?
The equation of motion would be
\frac {dv}{dt} = -k v
Can you integrate that?
physicsss
Oct1-04, 03:06 AM
Do I get lnv=-kt ? What do I need to do after I find what k is?
Hypercase
Oct1-04, 03:58 AM
Whats the answer given in your reference book?
-Cheers.
physicsss
Oct1-04, 04:21 AM
The answer is 10m, and i have no idea how they got it
poolwin2001
Oct1-04, 04:32 AM
When you solve the differential eqn you will have 2 variables(1 from integration & other 'k')Use the initial conditions given to find them.
At t=0,v=? and one more.
Else,if you did definite integration ,you have to figure out k by the 2nd condition given.
HallsofIvy
Oct1-04, 08:46 AM
Do I get lnv=-kt ? What do I need to do after I find what k is?
Since ln v=-kt+ C (you forgot to add the constant), v= Ce-kt which has two unknown parameters, C and k. Now use the information you were given: "traveling at a speed of 2.4 m/s shuts off its engines at t = 0". Okay, when t=0, v= Ce-k(0)= C= 2.4. "it is noted that after 3.0 s its speed has dropped to half its original value" Okay, when t= 0, v= "half its original value" which is 2.4/2= 1.2 m/s. v= 2.4e-k(3)= 1.2 . Solve that for k.
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