I don't understand what inductors do

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SUMMARY

The discussion centers on the behavior of inductors in a circuit with a light bulb and an ideal battery. When a ferrous metal piece is introduced into the coil of the inductor, the inductance increases, resulting in a slower rise of current due to the larger inductance. Despite this, both configurations ultimately allow the same amount of current flow in a steady-state DC condition. The introduction of a reverse-biased diode across the inductor can demonstrate a flicker in the light bulb when the switch is opened, indicating the release of stored energy in the magnetic field.

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Hi! Here is probably a simple problem but I can't solve it:

We have an inductor (just a coiled wire) in series with a light bulb, connected to an ideal battery. The light bulb is shining and we measure the intensity of light. Now we introduce a metal piece inside the coil. AFTER the piece is placed inside, we measure the intensity of the light again. Will there be any difference in the intensity of light and why?

Help me please!
 
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Inductance is the ability to store energy during field growth (field moment).

In either case, the wire itself has the same amount of resistance. So, in the end, BOTH cases show the same amount of current flow.

BUT, in the first case, the air-core in the coil allows a faster field moment (lower inductance).
In the second case (with ferrous insert), the circuit current will grow more slowly as the now LARGER inductance takes more time to build it's field.

Except for a slightly larger amount of energy stored in fields, and slightly slower rising of current at switch closure, there is no difference in the circuits from the final PURE DC condition.

If you connect a diode reverse-biased across the far end of the winding and the opposite bulb terminal you can also see a small flicker when you open the switch and the field collepses. The field energy is released a pulse of emf.
 

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