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awertag
Dec11-10, 03:00 PM
1. The problem statement, all variables and given/known data

Two people with a combined mass of 120 kg climb into an old car with worn out shock absorbers causing the springs to compress by 7.36 cm. Then, when the car hits a bump in the road it oscillates up and down with a period of 1.35 s.

(1) Find the total load supported by the springs.

(2) Find the mass of the car.




2. Relevant equations

T = 2pi (m)**.5 / (k)**.5

pi as in 3.1415... T= period k=spring constant **.5 as in radical

also note /\ means: delta/change in

3. The attempt at a solution

Fsp=mg
k/\x=mg
k(.0736)=(120)(9.8)
k=15978.2609 N/m


then plug into above equation:

1.35=[2pi(m)**.5]/(15978.2609)**.5

got incorrect answer of m= 71851.6587 kg

good help would be greatly appreciated!!!!

Rick88
Dec11-10, 03:33 PM
use k\Deltax = mg to find k. To do this, use the information given when the car is at rest. So m=120kg, \Deltax = 7.36cm .

Once you found k, plug the value in the other equation ( T = 2\pi ...) to find m.


R.

awertag
Dec11-10, 04:05 PM
thanks for replying rick, but that's what i did...i believe. Can you show me the difference?

Rick88
Dec11-10, 04:16 PM
You are absolutely, right. I beg your pardon.

However, my answer for m is completely different from yours.
I get m = 738kg.

Try solving again the second equation.
I would suggest you to square both sides so to get rid of the square root, if you hadn't done so already.

R.

awertag
Dec11-10, 04:21 PM
Wow, thank you so much!!! I squared both sides and that did the trick, really cleaned up the algebra. Have a great day! :)

Rick88
Dec11-10, 04:37 PM
Glad to be of help :)

Thanks, have a great day yourself!


R.