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Sushmita
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Homework Statement
[/B]
A particle of mass 'm' is initially in a ground state of 1- D Harmonic oscillator potential V(x) = (1/2) kx2 . If the spring constant of the oscillator is suddenly doubled, then the probability of finding the particle in ground state of new potential will be?
(A) 21/4/(1+ 21/2)
(B) 25/4/(1+21/2)
(C) 2/(1+21/2)
(D) 23/2/(1+21/2)
Homework Equations
I calculated state with the wave function of one dimensional harmonic oscillator given by
Ψ = (k/πħ)¼ exp (-kx2/2ħ)
When k was doubled, new wave function becomes
Ψ'= (2k/πħ)¼ exp (-2kx2/2ħ)
The Attempt at a Solution
I tried solving the question by calculating the probability by finding the inner product of the two but I cannot solve it
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