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Faiza
Oct3-04, 04:13 PM
Consider the following statement made by a student about a book at rest on a level table:

"The two forces exerted on the book are the normal force directed up and the weight of the book directed down. These are equal in magnitude and opposite to one another. By newton's third law they are a third law force pair so the normal force is always equal to the weight of the book."
Do you agree with the student? Explain?

Faiza
Oct3-04, 04:38 PM
No one ?????????????????????????????????

Faiza
Oct3-04, 04:39 PM
i disagree maybe cuz that the normal force and weight are not acting on each other so it doesnt satisfy newtons 3rd law action-reaction pair?????????

e(ho0n3
Oct3-04, 05:25 PM
You are right to disagree but your reasoning is wrong. Newton's 3. law involves the forces on two objects, i.e. the force the table exerts on the book is equal in magnitude but opposite in direction to the force the book exerts on the table.

e(ho0n3
Oct3-04, 05:30 PM
I disagree with your disagreeing :) The normal force and the weight act on the same body to give a resultant zero force. They are an action-reaction pair by Newton's third law because otherwise if the two forces did not cancel each other out then the book would be free to travel through the table.
No it is not an action-reaction pair because both forces are acting on the same body.

arildno
Oct3-04, 05:31 PM
vsage:
You're simply wrong!
There's actually two action/reaction pairs here:
Weight of book/book's force on the Earth
Normal force on book from table/Normal force from book on table.

Weight of book/Normal force on book from table is not an action/reaction pair.

arildno
Oct3-04, 05:35 PM
Air resistance and static friction has no relevance here.