physicsuser
Oct6-04, 04:21 PM
need to prove this
\frac{\urcorner P \equiv false}{P \equiv true}
here is what I did
using Leibniz
\frac{X \equiv Y}{E[z:=X] \equiv E[z:=Y]}
X=\urcorner P
Y=false
E:\urcorner z
z=z
\frac{\urcorner P \equiv false}{\urcorner\urcorner P \equiv \urcorner false}
since \urcorner\urcorner P \equiv P
and \urcorner false \equiv true
\frac{\urcorner P \equiv false}{P \equiv true}
is this a proof?
\frac{\urcorner P \equiv false}{P \equiv true}
here is what I did
using Leibniz
\frac{X \equiv Y}{E[z:=X] \equiv E[z:=Y]}
X=\urcorner P
Y=false
E:\urcorner z
z=z
\frac{\urcorner P \equiv false}{\urcorner\urcorner P \equiv \urcorner false}
since \urcorner\urcorner P \equiv P
and \urcorner false \equiv true
\frac{\urcorner P \equiv false}{P \equiv true}
is this a proof?