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leoflc
Oct10-04, 08:36 PM
Can someone show me that f(x, t) = A\cos(K(x-vt) + \phi) is in fact a solution of the wave equation?
I kind of know how to show it by using calculus, but is there other way to show it?

Thank you very much!

Fredrik
Oct10-04, 09:48 PM
Any function f that can be expressed as

f(x,t)=g(x-vt)

satisfies the wave equation. You don't even have to know what g is to show it.

leoflc
Oct10-04, 10:35 PM
Could you please show me a little more? I don't really get it why that will satisfie the wave equation...
Thank you very much!

Fredrik
Oct10-04, 11:24 PM
We're supposed to give hints here, not complete answers, but if you compute the second-order partial derivative

\frac{\partial^2 f(x,t)}{\partial t^2}

using the formula

f(x,t)=g(x-vt)

you're almost there. Does the result look anything like any other second-order partial derivative that appears in the wave equation?

leoflc
Oct11-04, 12:31 AM
Thanks, I'll give it a try.
But I'm just wondering, is there any other way to show it beside using calculus?
Thanks again!

Fredrik
Oct11-04, 12:50 AM
I don't think so. The wave equation is a partial differential equation, so any explanation would have to involve derivatives in some way.

I'm pretty sure that there's no easier way to understand the wave equation than the way I suggested. You should note that the graphs of the functions h_t, defined by

h_t(x)=g(x-vt)

can be thought of as the individual frames of a "movie" that shows the graph of g moving with velocity v.