Apatite

[chawki]

1. The problem statement, all variables and given/known data
Apatite (Ca5(PO4)3F) is used to manufacture fertilizer.

2. Relevant equations
How many kilograms of pure phosphorus (P) is included in 1150 kg of apatite?



3. The attempt at a solution
How we solve this, tell me only first step...
we can't even use the composition percentage law :grumpy:

[chemisttree]

Start with the forumla weight of apatite. Convert to moles.

Can you take it from there?

[chawki]

can you please tell me how to find the formula weight?
i have learnt chemistry ages ago..and it was in french..

maybe you meant the molar mass ? if it's that, then it is 504.31g/mol
504.31 = 1150000/n
n= 1150000/504.31
n= 2280.34mol

[chemisttree]

Right, that's how many moles of apatite. How many moles of phosphorous per mole of apatite?

[chawki]

That's where i'm stuck

[chemisttree]

Just look at the empirical formula. You do this part by inspection... nothing to calculate.

[chawki]

1mole

[chemisttree]

So if you were given 1 mole of Ca5(PO4)3F, you would get only one mole of P out of it?

[chawki]

i'm not sure, i'm confused

[chawki]

mp/30.97 = 1150000/504.31
mp= 7062.22g

[chemisttree]

AxBy gives you x moles of A and y moles of B per mole of AxBy.

How about the moles of P in one mole of Ca5(PO4)3F?

[chawki]

Three

[chawki]

So if you were given 1 mole of Ca5(PO4)3F, you would get only one mole of P out of it?

Not necessarly i think

[chawki]

mp/30.97 = 1150000/504.31
mp= 7062.22g

70622.23

[chawki]

Please tell me if i'm right

[Borek]

No. You have still ignored fact that there are three moles of P per apatite molecule.

[chawki]

mp/3*30.97 = 1150000/504.31
mp= 211866.709g
mp=211.866Kg

[chawki]

Please reply to my posts!

[Borek]

We are not your private tutorial service, aren't we?

Watch significant figures.

[chawki]

No, You are not. and i want to say that i appreciate having time for posting and replying.
God bless you all.