Physics math question

[EdenKhan]

Im pretty bad at these physics math problems and our book doesnt go over how to do them very much so I was wondering if I could get some help..

The problem is The weight of the atmosphere above 1 square meter of the earth's surface is 100 000 newtons. If the density of the atmosphere were a constant 1.2 kg/m(cubed), calculate where the top of the atmosphere would be.

Okay so we have the weight of the atmosphere as 100,000 newtons, the density is 1.2 kg/m(cubed). We learned that the pressure of the atmosphere is 100,000 newtons per meter squared, or 100 kilo pascals.

There a special formula in our to calculate how high the atmosphere is based on the density or the pressure?

thanks very much

[Vadim]

basically what you would want to do there, since you already know two of the dimensions of the volume(length=1m and width=1m), is figure out what the 100,000N is in kg and divide that by how many kilos it is per m^3. because you have a 1x1 square, the number of cubic meters will also be the height, because 1x1xY=Y