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RedX
Feb26-11, 09:07 PM
This is probably an easy question, but my math is not good enough to answer it.

For Gaussian integrals:

\frac{\int \Pi_i [dx_i] x_k x_l e^{-\frac{x_i A_{ij} x_j}{2}}} {\int \Pi_i [dx_i] e^{-\frac{x_i A_{ij} x_j}{2}}}=A^{-1}_{kl}

As far as I understand it, in QFT, Aij is a local operator. So Aij might be at most block diagonal, with very tiny sub-blocks corresponding to derivative terms (to know the derivative you only need to know the field an infinitismal distance away). Hence A-1ij should be block diagonal too, with tiny sub-blocks of the same dimension.

So how is it that the propagator G(x-y)=-iA^{-1}_{xy} doesn't seem to vanish for (x-y) not infinitismal?

Also does anyone know of a good math book written for improving the math of physics students?

weejee
Feb27-11, 03:04 AM
Hence A-1ij should be block diagonal too, with tiny sub-blocks of the same dimension.

I don't think this is true.

RedX
Feb27-11, 11:30 AM
I don't think this is true.

Yeah. The matrix A was never block diagonal to begin with: I don't know what I was thinking there. Just because it has only nearest neighbors on the diagonals doesn't mean it's block diagonal. So I think in general the inverse is global.

homology
Feb28-11, 09:50 AM
Hassani has a text on mathematics for physicists that quite complete and fairly modern and well written.