View Full Version : another challenging logarithmic question
hibachii
Mar9-11, 12:48 AM
1. The problem statement, all variables and given/known data
Combine into one log
log√x + 1 + ( 9log x )
2. Relevant equations
-
3. The attempt at a solution
I tried converting log√x + 1 to log(x+1)^(1/2)
1. The problem statement, all variables and given/known data
Combine into one log
log√x + 1 + ( 9log x )
2. Relevant equations
-
3. The attempt at a solution
I tried converting log√x + 1 to log(x+1)^(1/2)
No, you can't do that, for a lot of reasons.
Write √x as x1/2. Use the properties of logs to write log x1/2 in a different way.
Use the properties of logs to write 9logx in a different form.
Assuming that log here means log10, 1 = log10(10).
hibachii
Mar9-11, 01:18 AM
i dont get what you mean. How do u do the question?
The policy of this forum is that we don't do homework problems - you do them. I've given you some starting points, and now it's up to you. Open your book to where they define the properties of logarithms.
Suk-Sci
Mar17-11, 09:19 AM
Hi hibacii.....
You can use the property
nlogx=log(x)^n
and
Logx+logy+logz=Log(xyz)
and also
1=log10
I hope this helps you...
Thanx
Suk-Sci
HallsofIvy
Mar17-11, 09:25 AM
Do you mean
log(\sqrt{x+ 1}+ 9log(x)
or
log(\sqrt{x})+ 1+ 9log(x)
I think Mark44 was interpreting this as the latter. The former can be combined by using the laws of logarithms
blog(a)= log(a^b)
and
log(a)+ log(b)= log(ab)
Suk-Sci
Mar17-11, 09:28 AM
Did i do anything wrong i my last commment.....cause even i am a beginier
Suk-Sci
Mar17-11, 09:33 AM
I GOT IT!!!! even i said the same thing....
Thanx....
Suk-Sci
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