Understanding and Solving Trigonometry Equations: Tips and Tricks

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SUMMARY

The discussion centers on solving the trigonometric equation sec²X + tan²X = 6. Participants clarify that sec²X can be expressed using the Pythagorean identity sec²X = tan²X + 1, allowing for simplification of the equation. The transformation leads to tan²X + 1 + tan²X = 6, which can be further simplified to find the value of tan²X. This method effectively utilizes trigonometric identities to solve the equation.

PREREQUISITES
  • Understanding of trigonometric identities, specifically secant and tangent functions.
  • Familiarity with Pythagorean identities in trigonometry.
  • Basic algebra skills for manipulating equations.
  • Knowledge of how to square trigonometric functions.
NEXT STEPS
  • Study the derivation and application of Pythagorean identities in trigonometry.
  • Learn how to manipulate and solve trigonometric equations using identities.
  • Explore advanced trigonometric functions and their properties.
  • Practice solving various trigonometric equations to enhance problem-solving skills.
USEFUL FOR

Students studying trigonometry, educators teaching trigonometric concepts, and anyone looking to improve their skills in solving trigonometric equations.

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Homework Statement



Hi,
This isn't a homework question, I am having a bit of trouble with some Trig equations. If you are worried that you are answering a homework question please give me the solution to a similar question.

Homework Equations



When we have a trig equation like sec2X + tan2X = 6.

I know that sec is equal to 1/cos, and tan is equal to sin/cos, but what do I do with the square? Do I square all the terms or just the denominator?

The Attempt at a Solution



I have tried many times, to many to list here!

Thanks for your help
Dominic
 
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Hint: is there a Pythagorean identity that relates secant and tangent?
 
Hi Dominic! :wink:
Dragonetti said:
When we have a trig equation like sec2X + tan2X = 6.

I know that sec is equal to 1/cos, and tan is equal to sin/cos, but what do I do with the square? Do I square all the terms or just the denominator?

The whole thing …

tan2x = sin2x/cos2x :smile:

(and you can also use one of the standard https://www.physicsforums.com/library.php?do=view_item&itemid=18"

sec2x = tan2x + 1, same as 1/cos2x = sin2x/cos2x + cos2x/cos2x :wink:)​
 
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