PDA

View Full Version : the scalar partner of Majorana particle in SUSY


Accidently
Mar20-11, 03:10 AM
For example, the right-handed sneutrino. It can decay into both (s)leptons and anti-(s)leptons, so it is also the anti-particle of itself. I wonder how it looks like mathematically. If it is the same as normal scalar field, we can still distinguish its anti-particle (the complex conjugate).........

Bill_K
Mar21-11, 04:19 AM
I don't understand. νR is just a single state. So wouldn't its superpartner be a single state also, i.e. a real scalar?

Accidently
Mar21-11, 09:04 PM
I don't understand. νR is just a single state. So wouldn't its superpartner be a single state also, i.e. a real scalar?

I dont think it can be a real scalar. When we calculate the number density of the scalar n = -i(\phi\dot\phi^*-\dot\phi\phi^*), a real scalar cannot have a non-zero number density.

Let me rephrase this question: Think about the plane wave solution of this scalar \phi=Ae^{-i\rm{px}}. So its anti-particle \phi=Ae^{i\rm{px}} cannot be itself, unless it is real. But in this case, it cannot have a number density.

Bill_K
Mar22-11, 04:45 AM
What you're calling the number density is actually the charge density. Better read up on the Klein-Gordon equation!