logarithm equation

[vt33]

I need to solve 7^2x - 5*7^x - 24 =0. Am I on the right track by starting with 7^2x - 35^x - 24 = 0?

[Tide]

Let y = 7^x and see where that leads! :-)

[vt33]

I sorry, can elaborate. Are you talking about ax+by+c=0. If so, I'm still a little confused.

[Tide]

You did say "logarithm equation" in the title so I assumed you meant you want to solve this equation:

7^{2x} - 5 \times 7^x - 24 = 0

If so then set y = 7^x and since 7^{2x} = \left(7^x\right)^2 your equation becomes

y^2 - 5y - 24 = 0

which you can easily solve for y from which you can obtain x.