Confusing Physics Concepts Explained: Solving for Net Force and Fx

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SUMMARY

The discussion focuses on calculating net force and the force exerted by maneuvering thrusters during a space shuttle flight. The net force (Fnet) is derived from the equation Fnet = Fg - Fn, resulting in 9.414 x 10^6 N. The force required to achieve an upward acceleration of 29.4 m/s² for a shuttle mass of 570,000 kg is calculated using F = ma, yielding a force of 1.6758 x 10^7 N. The participant expresses confusion regarding the angle's impact on calculating Fx, indicating a need for further clarification on non-right angle force components.

PREREQUISITES
  • Understanding of Newton's Second Law of Motion (F = ma)
  • Knowledge of force components in physics
  • Familiarity with gravitational force calculations
  • Basic algebra for manipulating equations
NEXT STEPS
  • Study vector decomposition in physics for non-right angle forces
  • Learn about gravitational force calculations in different contexts
  • Explore advanced applications of Newton's laws in aerospace engineering
  • Review physics problems involving net force and acceleration
USEFUL FOR

Students studying physics, particularly those preparing for exams involving force calculations, and educators seeking to clarify concepts related to net force and acceleration in real-world applications.

Aladdinnas
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Why is physics so confusing?

Hey, it's my first time here...cz i need serious help.
My teacher gave us a review sheet for a big test, and he expects me to do it, even knowing that i jus moved into this class...
I've got most of the notes...but i still find things confusing...


For Question#1

Fnet = Fg-Fn
=(-5.586x10(p6))+(1.5x10(p7))
=9.414x10(p6)
F=ma
=29.4x5.7x10(p5)
=1.6758x10(p7)
I understand the concept so far...but since the angle will NOT create a right angle, i need to find another method of getting Fx.
 
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here is the question

1. During a space shuttle flight, an acceleration upward of 29.4m/s2[Y15X] is measured. Assuming that the shuttle has a mass of 570000kg, calculate the force that the small maneuvering thrusters would have to fire at to accomplish this. The main engines provide a force of 15000000N [Y] upward.
 
opps...i jus realized...this dosent belong in this forum...it's needs to be sent to the homework help forum
 

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