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RobertLelik
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< Mentor Note -- thread moved to HH from the technical physics forums, so no HH Template is shown >
Hello and thank you in advance for any help. I am currently studying physics and having difficulty working out a forces at equilibrium problem. With limited given variables, I am unable to see the path to a solution.
The problem is as such:
A 650N climber is resting mid-climb. If the co-efficient of friction between her feet and the vertical wall is 0.65 and the angle between the rope and the cliff is 8°, what is the tension in the rope? Find normal force (net force "X" direction)
Fg=650N (Ff÷Fn)=0.65 T = ? Fn = ?
Sum Fx = 0N Sum Fy = 0N
(Tx-Fn) = 0N (Ty+Ff) - Fg = 0N
And this is where I can't seem to find the relation...
Any help is greatly appreciated :)
Hello and thank you in advance for any help. I am currently studying physics and having difficulty working out a forces at equilibrium problem. With limited given variables, I am unable to see the path to a solution.
The problem is as such:
A 650N climber is resting mid-climb. If the co-efficient of friction between her feet and the vertical wall is 0.65 and the angle between the rope and the cliff is 8°, what is the tension in the rope? Find normal force (net force "X" direction)
Fg=650N (Ff÷Fn)=0.65 T = ? Fn = ?
Sum Fx = 0N Sum Fy = 0N
(Tx-Fn) = 0N (Ty+Ff) - Fg = 0N
And this is where I can't seem to find the relation...
Any help is greatly appreciated :)
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