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View Full Version : General Tensor contraction: Trace of Energy-Momentum Tensor (Einstein metric)


tetris11
Apr14-11, 10:32 AM
Okay so I have:

Eqn1) Tij=\rhouiuj-phij = \rhouiuj-p(gij-uiuj)

Where Tij is the energy-momentum tensor, being approximated as a fluid with \rho as the energy density and p as the pressure in the medium.


My problem:
Eqn2) Trace(T) = Tii = gijTij = \rho-3p

My attempt:

Tr(T) = Tii = gij[\rhouiuj-p(gij-uiuj)]
= [\rhogijuiuj-pgijgij+pgijuiuj)]
= \rhou - p + pu

which doesnt equal rho-3p (eqn2) as required, so I've done something wrong.
I think I've contracted incorrectly but I dont know why.... please help?

George Jones
Apr14-11, 11:15 AM
What are the following?

g^{i j} g_{i j} = ?

g^{i j} u_i u_j = ?

tetris11
Apr14-11, 03:06 PM
Well,
g^{i j} u_i u_j = 1

g^{i j} g_{i j} = ??
uh... g? or 0?

Might need to help me out here, maths isn't my first language...

Bill_K
Apr15-11, 05:00 AM
gij gij = δii = 4.

tetris11
Apr17-11, 10:45 AM
Cheers man, that actually makes complete sense - but just for the record:

gij gij = δii = n, where n is number of dimensions?

I'm just wondering how you knew it was four without knowing how dimensions it was.
Tensors aren't all 4-d, right?

TobyC
Apr17-11, 11:36 AM
Cheers man, that actually makes complete sense - but just for the record:

gij gij = δii = n, where n is number of dimensions?

I'm just wondering how you knew it was four without knowing how dimensions it was.
Tensors aren't all 4-d, right?

Well this is the 'Special & General Relativity' board so it was probably just a good guess?