Understanding the MO Energy Level Diagram for H3+ Cyclic Structure

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The discussion focuses on constructing a Molecular Orbital (MO) energy level diagram for the H3+ ion, specifically assuming a cyclic structure. Participants clarify that the basis set consists of three hydrogen 1s orbitals, leading to the formation of three molecular orbitals. The top orbital has no nodes and is filled with the two available electrons, while the other two orbitals each contain one node. This arrangement illustrates the delocalization of electrons across the hydrogen atoms, confirming theoretical expectations.

PREREQUISITES
  • Understanding of Molecular Orbital Theory
  • Familiarity with atomic orbitals, specifically hydrogen 1s orbitals
  • Knowledge of electron configuration and orbital filling principles
  • Basic concepts of molecular symmetry and delocalization
NEXT STEPS
  • Study the construction of MO diagrams for diatomic and polyatomic molecules
  • Learn about the implications of orbital nodes in molecular stability
  • Explore the concept of electron delocalization in cyclic structures
  • Investigate the properties and behavior of the H3+ ion in various chemical contexts
USEFUL FOR

Chemistry students, molecular physicists, and anyone interested in advanced concepts of molecular structure and bonding, particularly in relation to the H3+ ion.

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H3+ ion has been observed but its structure has been the cause of some controversy. Prepare a MO energy level diagram for H3+ assuming cyclic structure.




I have no idea how in the hell I am supposed to do this problem since the only MO diagrams we have done in class have been only with 2 atoms. Please can someone help?
 
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You may try H+ and H2 on the other side.
 
Okay, so your basis set is the three hydrogen 1s orbitals, right? Think of the productive ways that you can have those overlap and then start changing the phase of the orbitals one at a time to get the higher energy forms. There will be three molecular orbitals in all. They should look roughly like this:

X
X​
X


X
.​
O


X
O​
X

Where X indicates one phase, O indicates the other, and . indicates a node. So the one on the top has no nodes, the other two have one node each. These are a crude representation of the molecular orbitals. Each orbital can "hold" two electrons. You have two electrons to deal with in this case, so place them in the lowest energy orbital (the one with no nodes).

Some things to note:
1) You start with three atomic orbitals and you get three molecular orbitals. You MUST always end up with the same number of molecular orbitals as you had atomic orbitals.
2) The filled molecular orbital (the top one) represents delocalization of the electrons evenly between each hydrogen atom. This is what you would expect intuitively. This agreement is important!
 
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