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theacerf1
May9-11, 02:22 AM
Ok this question is in a cd quiz from a text book, i have no idea what the question even means or how to do it. Please help!

Let M =

 7 −3
15 −7 .

Find all 2 × 2 matrices

A =
[ a b
b d ]

such that AM = −MA.
(Note that the solutions wanted should have equal (1, 2)- and (2, 1)-entries b.)

theacerf1
May9-11, 02:32 AM
M =
[7 -3
15 -7]

a 2x2 matrix

HallsofIvy
May9-11, 08:42 AM
Did you even try? It is really just a matter of computation.

\begin{bmatrix}a & b \\ b & d\end{bmatrix}\begin{bmatrix}7 & -3 \\ 15 & -7\end{bmatrix}
= \begin{bmatrix}7a+ 15b & -3a- 7b \\ 7b+ 15d & -3b- 7d\end{bmatrix}
= -\begin{bmatrix}7 & -3 \\ 15 & -7\end{bmatrix}\begin{bmatrix}a & b \\ b & d\end{bmatrix}
= \begin{bmatrix}-7a+ 3b & -7b+ 3d \\ -15a+ 7b & -15b+ 7d\end{bmatrix}

So you must have 7a+ 15b= -7a+ 3b, -3a- 7b= -7b+ 3d, 7b+ 15d= -15a+ 7d, and -3b- 7d= -15b+ 7d.