forward force?

[DOMINGO79]

I am given the information: A water-skier is pulled behind a motorboat with a rope 8m long. As she is approaching a ramp, she pulls herself 2m to the side of the path of the boat. It creates an angle of 14.5 degrees.

I am asked:
1.) how much of the tow rope force is in the forward direction?
2.) how much of the tow rope force is sidewards?

How do i find that info when i am not given any additional infor?

[$id]

I am given the information: A water-skier is pulled behind a motorboat with a rope 8m long. As she is approaching a ramp, she pulls herself 2m to the side of the path of the boat. It creates an angle of 14.5 degrees.

I am asked:
1.) how much of the tow rope force is in the forward direction?
2.) how much of the tow rope force is sidewards?

How do i find that info when i am not given any additional infor?

You can resolve that into vertical and horizontal components

The one perpendicular to motion wouild be Tension in the rope * sin 14.5

the one parallel ( question 1) Would be T cos 14.5

I am not sure about that T actually is . The length of the rope doesnt help.

I hope that give you a start

Sid

[Doc Al]

Do not double post!

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