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romsofia
Jun23-11, 08:44 PM
Which form do you prefer, the integral form or differential form?

EDIT: Forgot to say I prefer the integral form.

fluidistic
Jun23-11, 08:47 PM
You forgot the tensor form! :D

Drakkith
Jun23-11, 08:49 PM
Where's the option for "Who's Maxwell and what do these two terms mean"?

romsofia
Jun23-11, 08:54 PM
You forgot the tensor form! :D

I'm unfamiliar with the tensor form o.o! It would probably make little sense to me :P



Where's the option for "Who's Maxwell and what do these two terms mean"?

They're 4 equations, and that ain't in this poll :P.

WannabeNewton
Jun23-11, 09:09 PM
I would have liked to see the differential forms version of Maxwell's equations, very elegant way of expressing them. But since they aren't up there I would have to go with the differential form because the del operator looks cool =D

atyy
Jun23-11, 09:16 PM
Where's the option for "Who's Maxwell and what do these two terms mean"?

http://www.youtube.com/watch?v=ZD5hz8EnyaE

yungman
Jun24-11, 02:12 AM
You need to use both.

Drakkith
Jun24-11, 05:15 AM
http://www.youtube.com/watch?v=ZD5hz8EnyaE

WTF was that?

Jimmy Snyder
Jun24-11, 07:28 AM
Which one of Maxwell's equations is your favorite? Mine is Faraday's equation.

Pranav-Arora
Jun24-11, 11:51 AM
Like the differential form!! Altough i have just started them. MIT lectures are great!! :smile:

clancy688
Jun24-11, 12:04 PM
Integral... how the hell am I supposed to calculate with the differential form without my head imploding? :redface:

Favourite one: Gauss's Law - the easiest concept to grasp imho. :shy:

dextercioby
Jun24-11, 02:22 PM
What's more beautiful than dF= 0 and \delta F=j ? :wink:

I like Serena
Jun24-11, 02:36 PM
I like this one best:
\square A^\alpha = \mu_0 J^\alpha
That is, all of Maxwell's equations rolled into one simple equation! :smile:

WannabeNewton
Jun24-11, 02:37 PM
What's more beautiful than dF= 0 and \delta F=j ? :wink:

Is \delta F the same as d(\star F) ?

dextercioby
Jun24-11, 02:42 PM
Essentially, up to a possible minus sign depending on the dimension of spacetime and metric signature , delta = * d * .

dextercioby
Jun24-11, 02:43 PM
I like this one best:
\square A^\alpha = \mu_0 J^\alpha
That is, all of Maxwell's equations rolled into one simple equation! :smile:

Well, not really, the fundamental gauge symmetry is missing in your equation.

I like Serena
Jun24-11, 02:48 PM
Well, not really, the fundamental gauge symmetry is missing in your equation.

I'm not familiar with fundamental gauge symmetry yet.
What is it?

Is it part of Maxwell's equations?

Antiphon
Jun24-11, 02:48 PM
The integral form is easier to visualize because the curls turn into line and surface integrals which naturally illustrate relationships between things like enclosed current and MMF.

dextercioby
Jun24-11, 02:52 PM
I'm not familiar with fundamental gauge symmetry yet.
What is it?

Is it part of Maxwell's equations?

Yes, the reason we use potentials is quantum mechanics and quantum field theory. A quantum theory of the electromagnetic field cannot be built without dealing with the gauge symmetry first.

cragar
Jun25-11, 04:47 AM
I like how we call them Maxwell's equations even tho it was Faraday and Heaviside that pretty much came up with them.

Pengwuino
Jun25-11, 05:03 AM
I like this one best:
\square A^\alpha = \mu_0 J^\alpha
That is, all of Maxwell's equations rolled into one simple equation! :smile:

As dexter was hinting at, Maxwell's equations can't be uniquely defined by that condition.

As far as the thread is concerned, the integral form of anything is noob-sauce.

I like Serena
Jun25-11, 05:57 AM
What's more beautiful than dF= 0 and \delta F=j ? :wink:

Aha!!!
I had to read up on Maxwell's equations again before I understood (again).
There (wiki) I also found your equations, which were not familiar to me.

But now I understand that your 2 equations are an alternate form that represent all of Maxwell's equations! :smile: