How Do You Calculate the Height of a Rock at Half Its Initial Speed?

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SUMMARY

The discussion focuses on calculating the height of a rock thrown upwards at half its initial speed using two methods: conservation of energy and kinematics. The rock has a mass of 22.8 KG and an initial kinetic energy (KE) of 28 Joules, with an initial velocity of 1.56721 m/s. The peak height reached by the rock is approximately 0.122807 meters. The conservation of energy approach effectively determines the height at half the initial speed.

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ok you have a rock of mass 22.8 KG
It has an initial KE of 28 Joules
This rock is thrown upwards with an initial velocity of 1.56721 m/s
It peak height is .122807 ( i hope that's right :confused:)
What is the height of the rock at half its initial speed?
If someone could just give me the right formula or head me in the right direction that would be great. :D
 
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One way is to use conservation of energy. As it rises, it loses KE (figure out how much) and gains PE.

Another way is to use kinematics: [itex]v_f^2 = v_i^2 + 2ad[/itex]
 
Thankyou, got it with conservation of energy. :D
 

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