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Blues_MTA
Jul3-11, 04:28 PM
According to http://www.aveox.com/DC.aspx The way to calculate the output of a DC motor in kRPMs is the formula

RPM of motor: kRPM = (V - RmI) / Kb

V= Voltage
Rm = Terminal Resistance
I = Current
Kb = Voltage Constant (V/kRPMs)



This insinuates that an increase in amperage leads to a decrease in RPMs? How is that Possible?

I know that Current:Torque and Voltage:Speed, but isnt Voltage = I*R, so an increase in current should consequently lead to an incresed voltage?

david90
Jul5-11, 10:17 AM
You should read up on back emf of a dc motor. As rpm increases, an opposing voltage aka back emf (@ the armature terminal) will also increases. The back emf opposes the supply voltage and thus reduces the current to the dc motor. Less rpm = less back emf = more current.

uart
Jul5-11, 11:28 AM
This insinuates that an increase in amperage leads to a decrease in RPMs? How is that Possible?

Yes, the equation shows that if the current increases, all other variables remaining constant, that the speed decreases. The causality is actually the other way around however. If you increase the load (torque) then the speed decreases and this causes the current to increase.