Coefficient of friction

[Kdawg]

A 52-N sled is pulled across a cement sidewalk at a constant speed. A horizontal force of 36 N is exerted. What is the coefficient of sliding friction between the sidewalk and the metal runners of the sled?
What formulas would I use in this problem?

[nelufar]

A 52-N sled is pulled across a cement sidewalk at a constant speed. A horizontal force of 36 N is exerted. What is the coefficient of sliding friction between the sidewalk and the metal runners of the sled?
What formulas would I use in this problem?


It is simple !
Use the formula,
F = {\mu}_s * N
where F is the horizontal force and N is the normal force, which is equal to the weight of the sled. (I assume that the cement sidewalk is placed horizontally).

[gauravkukreja]

Notice that the body is moving with uniform accelaration.
This means that the net force acting on the body is 0.
Therefore, \mu * 52 N = 36 N
This gives, \mu = 36 / 52

[brewnog]

The body is moving with uniform *velocity*, not acceleration, otherwise the net force on the body would not be zero.